// Finds the sum of all 3 or 5 multiples below 1000

void problem1(void){

	int sum, i;
	sum = 0;

	for(i=1;i<1000;i++){

		if(i%3 == 0 || i%5 == 0){

			sum = sum + i;

		}


	}

	printf("Sum = %d", sum);

}

